View the step-by-step solution to:

# Repair Costs: Refrigerators In a random sample of 60 refrigerators, the mean repair cost was %150. Assume the population standard deviation is %15.

Repair Costs: Refrigerators In a random sample of 60 refrigerators, the mean repair cost was %150.00. Assume the population standard deviation is %15.50. Construct a 99% confidence interval for the population mean repair cost. Interpret the results.

We are given data that Sample mean(xbar) = 150 population standard deviation( ﻿ σ ﻿ ) = 15.5 sample size(n) = 60 Z... View the full answer

for 99 % confidence interval area outside tailed portion = 0.01/2 = 0.005 also for 0.995... View the full answer

﻿ 1 4 4 . 8 4 ≤ μ ≤ 1 5 5 . 1 6 ﻿ We have... View the full answer

### Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

### -

Educational Resources
• ### -

Study Documents

Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

Browse Documents