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Stuck on below 3 problems. thanks. 1) In a survey of 3497 adults, 1485 say they have started paying bills online in the last year.

Stuck on below 3 problems. Need, help... thanks.



1) In a survey of 3497 ​adults, 1485 say they have started paying bills online in the last year.

Construct a​ 99% confidence interval for the population proportion. Interpret the results.


A​ 99% confidence interval for the population proportion is (___, ____)

​(Round to three decimal places as​ needed.)

__________________________________________________________________________


2) Construct the confidence interval for the population mean μ.


C = 0.95​, x = 15.6​, σ = 2.0​, and n = 55


A 95​% confidence interval for μ is (____, _____)  is

(Round to one decimal place as​ needed.)


_____________________________________________________________________________


3) A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who are confident with their​ country's banking system. His estimate must be accurate within 3​% of the population proportion.

​(a) No preliminary estimate is available. Find the minimum sample size needed.

​(b) Find the minimum sample size​ needed, using a prior study that found that 32​% of the respondents said they are confident with their​ country's banking system.

​(c) Compare the results from parts ​(a) and ​(b).


(a) What is the minimum sample size needed assuming that no prior

information is​ available?


n = ___  ​(Round up to the nearest whole number as​ needed.)

Top Answer

question 1 The confidence interval for proportion is given by CI= p` + z c *sqrt(p`q`/n) Where p` is the sample proportion we... View the full answer

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