**Normal distribution** has mean µ=200 and a standard deviation σ = 50.

Sample of n = 64 were selected. What is the probability that the sample mean

will be between 180 and 230? ........ Tip: Apply formula S = σ/√n to find standard deviation of sample mean,

use this standard deviation to convert 180 and 230 to z-score

and then use Appendix Table for Normal distribution.

**Show work.**

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we want to find P(180<x<230) we start by standardizing this to z score... View the full answer

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We are given values, Mean( μ ) = 200 standard deviation ( σ ) = 50 sample size(n) = 64 Z score for mean... View the full answer

P ( 1 8 0 < x... View the full answer