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# Normal distribution has mean =200 and a standard deviation = 50. Sample of n = 64 were selected. What is the probability that the sample mean will be...

Normal distribution has mean µ=200 and a standard deviation σ = 50.

Sample of n = 64 were selected. What is the probability that the sample mean

will be between 180 and 230? ........ Tip: Apply formula S = σ/√n to find standard deviation of sample mean,

use this standard deviation to convert 180 and 230 to z-score

and then use Appendix Table for Normal distribution.

Show work.

we want to find P(180&lt;x&lt;230) we start by standardizing this to z score... View the full answer

We are given values, Mean( ﻿ μ ﻿  ) = 200 standard deviation ( ﻿ σ ﻿  ) = 50 sample size(n) = 64 Z score for mean... View the full answer

The [dale shows the area to the left of a z-score: .i: I.|1 I .I-C |.| '. I I“ .I.1-: 1 II'.
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0.0664 00100 0.0130 0.6222 0.0808 0.6844 0.08?)
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﻿ P ( 1 8 0 &lt; ​ x... View the full answer

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