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Determine the 99% condence interval estimate for the population mean of a normal distribution given n =144, U: 121, and }_(= 1,399. The 99% condence...

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Determine the 99% confidence interval estimate for the population mean of a normal distribution given n =144, U: 121, and }_(= 1,399. The 99% confidence interval for the population mean is from D to D.
{Round to two decimal places as needed. Use ascending order.)

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Critical Z=- NORMSINV(0.01/2)=2.58 99% CI=... View the full answer

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