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Hey I am confused about how to start this question. According to a recent study, 38% of all women will suffer a hip fracture because of osteoporosis...

Hey I am confused about how to start this question.


According to a recent study, 38% of all women will suffer a hip fracture because of osteoporosis by the age of 85. If six women aged 85 are randomly selected, what is the probability that 

3 marks a. None of them will suffer (or has suffered) a hip fracture due to osteoporosis?

6 marks b. At least four of them will suffer (or have suffered) a hip fracture due to osteoporosis?

4 marks c. Fewer than two of them will suffer (or have suffered) a hip fracture due to osteoporosis?

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