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# I need help solving this hypergeometric equation for applied statistics alt="7787113" /> ATTACHMENT PREVIEW Download attachment Screen Shot 2019-04-04 at 2.35.47 PM.png Score : O of 1 pt 1 1 of 12 ( 7 complete ) + HW Score : 58.33% , 7 of 12 pts 5. 2. 43 : = Question Help If we sample from a small finite population without replacement , the binomial distribution should not be used because the events are not independent . If sampling is done without replacement and the outcomes belong to one of two types , we can use the hypergeometric distribution . If a population has A objects of one type , while the remaining B objects are of the other type , and if n objects are sampled without replacement , then the probability of getting x objects of type A and M - * objects of type B under the hypergeometric distribution is given by the following formula . In a lottery* game , a better selects four numbers from 1 to 52 ( without repetition ) , and a winning four -number combination is later randomly selected . Find the probabilities of getting exactly two winning numbers with one ticket . ( Hint : Use A = 4 , B = 48 , 17 = 4 , and * = 2. ) A ! B ! ( A + B ) !` P( x ) = [A - X )!X ! ( B - 17 + X ) ! ( 7 - X) !&quot; ( A + B - 1) In ! P ( 2) = [ ] ( Round to four decimal places as needed . )

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