Let X have pdf fX(x) = 2 / 9 (x+ 1 ), -1 <=x<= 2.
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<ul><li>Let X have pdf fX(x) = <span class="hljs-number">2</span>/<span

class="hljs-number">9</span>(x+<span class="hljs-number">1</span>), <span class="hljs-number">-1</span>&lt;=x&lt;=<span class="hljs-number">2.</span> Find the pdf <span class="hljs-keyword">of</span> Y = x^2</li></ul>

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