According to the following table of joint probabilities, (a) Determine P(A1|B1). (b) Determine P(A2|B1). (c) Do the answers to parts (a) and (b) sum
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# According to the following table of joint probabilities, alt="Screenshot 2019-09-30 at 8.18.13 PM.png" />(a) Determine P(A1|B1). (b) Determine P(A2|B1). (c) Do the answers to parts (a) and (b) sum to 1? Is this a coincidence? (d) Determine P(A1|B2)(e) Determine P(B2|A1)(f) Did you expect the answers to parts (a) and (b) to be reciprocals? Why is this impossible (unless all probabilities are 1)? (g) Are events A and B independent? ATTACHMENT PREVIEW Download attachment Screenshot 2019-09-30 at 8.18.13 PM.png

a) p ( A 1 / B 1 ) = p ( B 1 ) p ( A 1 B 1 ) = 0 . 7 0 . 4 = 7 4 ... View the full answer

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