Betty earned a score of 75 on her latest exam.The professor determined that all of the scores from this exam had a normal distribution with a mean of...
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Betty earned a score of 75 on her latest exam. The professor determined that all of the scores from this exam had

a normal distribution with a mean of 88 and a stand deviation of 5.

What is betty's Z score on the exam? Three decimal answer please explain

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here, mean () = 88
standard deviation (0 ) = 5
X = Betty's score on last exam = 75
so, the Z- score be:-
=
X - # y
75 - 88
=
= - 2.6
explanation:-
Betty's score in last exam is 2.6 standard...

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