There are 250,000 people attend the fair, 1% visit the pavilion for screening services equals
(0.01×250000)=2500 people, prevalence for hearing loss is 0.18×2500=450, 90% Sensitivity and 96% specificity, contingency table listed below:
Screening Test Present Absent Total= (a +b) =487 Positive (a +b) Hearing Lost Hearing Lost
(c+d) = 2013
Negative (c+z) Total: (a+c) = 450 (b+d) =2050 = 2,500
Calculation: 0.90a÷450, a= 0.90 ×450 or a=450, 0.96=d÷2, 050, d=0.96×2,050or d=1, 968, 0.91b=2,050-1,968=82, c=450-405=45
- Construct a 2-by-2 contingency table to determine the total number of people who fail the diagnostic test, which represents the target market for hearing aid sales.
- A total of 487 people tested positive for hearing loss and will be referred for follow-up diagnostic testing.
Screening testing Present Absent (hearing lost) (hearing lost)
(a + b) =402
(c + d)=85
Total (a+c) =405 (b+d) =82 (a+b+c+d) =487
0.99=a÷405, a=0.99×405or a=401, 0.99=d÷82, d=0.99×82or d=81, b=82-81=1, c =405-401=4
Recently Asked Questions
- State whether the actual data are discrete or continuous, and explain why. The number of limbs on each oak tree in a given forest.
- Hello, I am stuck on this problem, any help would be greatly appreciated. Thank you in advance.
- In A survey of 490 drivers from the South, 403 wear seatbelt. In a survey of 360 drivers from the Northeast, 272 wear seatbelt. At a=.05, can you support the