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# src="/qa/attachment/10702617/" alt="Screen Shot 2019-10-02 at 8.36.23 PM.png" />5 parts to this question given in the images Attachment 1 Attachment 2 Attachment 3 Attachment 4 ATTACHMENT PREVIEW Download attachment Screen Shot 2019-10-02 at 8.36.02 PM.png Suppose the following probabilities reflect the number of smart speakers (Google Home, Amazon Echo, etc.) per household for residents of Ann Arbor. X = number of smart speakers per Ann Arbor household 0 1 2 3 4 P(X = x) 0.28 0.46 0.20 0.05 0.01 Question 2 Subquestions 2.a 1 point(s) What is the expected number of smart speakers per household in Ann Arbor? (Select ALL that apply) I' m )'( = 1 smart speakers m p = 1 smart speakers m E()() = 1 smart speakers ﬂ )'( = 1.05 smart speakers m p = 1.05 smart speakers m E()() = 1.05 smart speakers ﬂ )'( = 2 smart speakers m p = 2 smart speakers m E()() = 2 smart speakers ATTACHMENT PREVIEW Download attachment Screen Shot 2019-10-02 at 8.36.23 PM.png Which of the following values correctly completes the following interpretation: (Note: no computations are needed here.) The average distance between the number of smart speakers per household in Ann Arbor is roughly smart speakers away from the mean number of smart speakers per household in Ann Arbor. 0 -0.4380 G O 0 0.0033 m 0.8761 ATTACHMENT PREVIEW Download attachment Screen Shot 2019-10-02 at 8.36.27 PM.png Find the probability that a randomly selected Ann Arbor household will have at least 2 smart speakers. O P(X &gt; 2) = 0.06 O P( 2 2) = 0.26 O P(X&gt; 2) = 0.19 O P(X 2 2) = 0.59 ATTACHMENT PREVIEW Download attachment Screen Shot 2019-10-02 at 8.36.32 PM.png Given that a randomly selected Ann Arbor household has at least 1 smart speaker, what is the probability that they will have more than 1 smart speaker? O P(X=1|X21)=0.6389 O P(X&gt;1|X21)=0_3611 O P(X21|X&gt;1)=0_3611 If you select 5 Ann Arbor households at random, what is the probability that exactly 2 households will have at least 2 smart speakers? (7 0.0676 (7 0.2600 (7 0.02739 (7 0.2739

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