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src="/qa/attachment/10702617/" alt="Screen Shot 2019-10-02 at 8.36.23 PM.png" />Screen Shot 2019-10-02 at 8.36.27 PM.pngScreen Shot 2019-10-02 at 8.36.32 PM.png


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Suppose the following probabilities reflect the number of smart speakers (Google Home, Amazon Echo, etc.) per household for residents of Ann Arbor. X = number of smart speakers per Ann Arbor household 0 1 2 3 4
P(X = x) 0.28 0.46 0.20 0.05 0.01 Question 2 Subquestions 2.a 1 point(s) What is the expected number of smart speakers per household in Ann Arbor? (Select ALL that apply) I'
m )'( = 1 smart speakers m p = 1 smart speakers m E()() = 1 smart speakers fl )'( = 1.05 smart speakers
m p = 1.05 smart speakers
m E()() = 1.05 smart speakers
fl )'( = 2 smart speakers m p = 2 smart speakers m E()() = 2 smart speakers

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Which of the following values correctly completes the following interpretation: (Note: no computations are needed here.) The average distance between the number of smart speakers per household in Ann Arbor is roughly smart speakers away from the
mean number of smart speakers per household in Ann Arbor. 0 -0.4380
G O 0 0.0033
m 0.8761

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Find the probability that a randomly selected Ann Arbor household will have at least 2 smart speakers.
O P(X > 2) = 0.06
O P( 2 2) = 0.26
O P(X> 2) = 0.19
O P(X 2 2) = 0.59

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Given that a randomly selected Ann Arbor household has at least 1 smart speaker, what is the probability that they will have more than 1 smart
speaker? O P(X=1|X21)=0.6389
O P(X>1|X21)=0_3611 O P(X21|X>1)=0_3611 If you select 5 Ann Arbor households at random, what is the probability that exactly 2 households will have at least 2 smart speakers? (7 0.0676
(7 0.2600
(7 0.02739 (7 0.2739

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