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Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a

standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P72, the 72-percentile. This is the temperature reading separating the bottom 72% from the top 28%.

P72 =_____ °C

(Round answer to three decimal places)

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X ~ N ( = 0 , = 1 ) P ( X < ? ) = 72% = 0.72 Looking for... View the full answer

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