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# alt="11.jpeg" />Please help me wit these Please please please Attachment 1 Attachment 2 ATTACHMENT PREVIEW Download attachment 11.jpeg ATTACHMENT PREVIEW Download attachment 1221212.jpeg 8. We have looked at situations in which we need to determine the number of possible routes between two places. We can look at the situation below as 9 steps, six of which must be East and three of which must be South. This gives us 9! 3!6! possible routes. The calculation 9! 3!6! is equivalent to ,C3 (or ,(6). Explain clearly why you could solve this question using combinations, and why this is equivalent to considering permutations with repeated items. 4 marks

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