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Researchers collected information on the body parts of a new species of frog. The thumb length for the female frog

has a mean of 8.59

8.59 mm and a standard deviation of 0.63

0.63 mm. Let x denote thumb length for a female specimen.

a. Find the standardized version of x.

b. Determine and interpret the​ z-scores for thumb lengths of 10.1

10.1 mm and 8.5

8.5 mm. Round your answers to two decimal places.

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Solution: -
Given that
X = Thumb Cengits of the female frog
X N N ( 1 , - )
Mean My= f.59
S . D
0 . 6- 3
( a )
Standard Version of X,
7 =
x - M
x -
I =
0. 63
( 6 )
n =
10 :1
1001 - 6:59
0 -...

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