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Assume that a set of test scores is normally distributed with a mean of 80 and a standard deviation of 10 Use

the​ 68-95-99.7 rule to find the following quantities.

the percentage of scores less than 80

the percentage of scores greater than 90

the percentage of scores between 60 and 90

Also what formula is used

Top Answer

using excel commands , the results are: p(x<80) =NORM.DIST(80,80,10,1) = 0.5000... View the full answer

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