Question

# A random sample of 5778 physicians in Colorado showed that 2927 provided at least some charity care (i.e., treated

poor people at no cost).

(a) Let *p* represent the proportion of all Colorado physicians who provide some charity care. Find a point estimate for *p*. (Round your answer to four decimal places.)

(b) Find a 99% confidence interval for *p*. (Round your answers to three decimal places.)

lower limit

upper limit

Give a brief explanation of the meaning of your answer in the context of this problem.

99% of the confidence intervals created using this method would include the true proportion of Colorado physicians providing at least some charity care.

99% of all confidence intervals would include the true proportion of Colorado physicians providing at least some charity care.

1% of the confidence intervals created using this method would include the true proportion of Colorado physicians providing at least some charity care.

1% of all confidence intervals would include the true proportion of Colorado physicians providing at least some charity care.

(c) Is the normal approximation to the binomial justified in this problem? Explain.

Yes; *np* > 5 and *nq* > 5.

No; *np* < 5 and *nq* > 5.

Yes; *np* < 5 and *nq* < 5.

No; *np* > 5 and *nq* < 5.

#### Top Answer

(A) 0.5066 (B) lower limit = 0.490 upper limit = 0.524 99% of the confidence... View the full answer