Question

**I need help with both **

1.Case studies showed that out of 10,647 convicts who

escaped from certain prisons, only 7347 were recaptured.

**2.Case studies showed that out of 10,392 convicts who escaped from certain prisons, only 8193 were recaptured. **

(a) Let *p* represent the proportion of all escaped convicts who will eventually be recaptured. Find a point estimate for *p*. (Round your answer to four decimal places.)

(b) Find a 99% confidence interval for *p*. (Round your answers to three decimal places.)

lower limit

upper limit

Give a brief statement of the meaning of the confidence interval.

1% of all confidence intervals would include the true proportion of recaptured escaped convicts.

1% of the confidence intervals created using this method would include the true proportion of recaptured escaped convicts.

99% of all confidence intervals would include the true proportion of recaptured escaped convicts.

99% of the confidence intervals created using this method would include the true proportion of recaptured escaped convicts.

(c) Is use of the normal approximation to the binomial justified in this problem? Explain.

Yes; *np* > 5 and *nq* > 5.

Yes; *np* < 5 and *nq* < 5.

No; *np* < 5 and *nq* > 5.

No; *np* > 5 and *nq* < 5.

#### Top Answer

1. (a) Let p represent the proportion of all escaped convicts who will eventually be recaptured. Find a point estimate for p... View the full answer