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A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for

their most recent business trip. 19% responded that it was for an internal company visit. Suppose 950 business travelers are randomly selected. 

a. What is the probability that more than 20% of the business travelers say that the reason for their most recent business trip was an internal company visit? 

b. What is the probability that between 18% and 20% of the business

Top Answer

a) P = 0.19 z(0.20) = (0.20-0.19)/sqrt[0.19*0.81/950] = 0.786 p-value to the right of z = 0.786 is : P(p... View the full answer

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