Then mean cholesterol levels of women age 45-59 in ghana, nigeria, and seychelles is 5.1 mmol/l and the standard
deviation is 1.0 mmol/l( Lawes, Horn, Law & Rodgers, 2004). Assume that cholesterol levels are normally distributed.
a. state the sample variable
b. Find the probability that a woman age 45-59 in ghana has a cholesterol level above 6.2mmol/l (considered a high level)
c. suppose doctors decide to test the woman cholesterol level again and average the twi valuers. find the probability that this woman;s mean cholesterol level for the two values. find the probability that this woman;s mean cholesterol level the two tests is above 6.2mml/l
d. suppose doctors being very conservative decide to test the woman's cholesterol level a third time and average the three values. find the probability that this woman's mean cholesterol level for this woman after three tests is above 6.2 mmol/l
e. If the sample mean cholesterol level for this woman after three tests is above 6.2 mmol/l, who could you conclude?
Given in the question Mean = 5.1 Standard deviation = 1 Solution (a) Cholesterol levels of women is the random variable.... View the full answer