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1. The American Academy of Periodontology released a survey...

1. 

The American Academy of Periodontology released a survey revealing that 27% of US adults admit they lie to their dentist about how often they floss their teeth. Periodontist Dr. Garcia believes that the percentage seems low, so he decides to conduct his own hypothesis test to determine the true proportion. What should he write as the null and alternative hypotheses for this situation? (2 points)

aH0: p = 0.27; Ha: p > 0.27
bH0: p = 0.27; Ha: p < 0.27
cH0: p = 0.27; Ha: p ≠ 0.27
dH0: µ = 0.27; Ha: µ > 0.27
eH0: µ = 0.27; Ha: µ < 0.27

2. 

Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found that actually 20% are late to work once a week. What does the test statistic calculation look like in this situation for an appropriate hypothesis test? (2 points)

Image transcription text

O 0.16-0.20 Z= 0.20 ( 0.80 ) 25 O Z = 0.20-0.16 0.20 ( 0.16) 25 O Z = 0.20-0.16 0.20 ( 0.80 ) 25 O Z = 0.20-0.16 0.16 ( 0.84 ) 25 O Z= 0.16-0.20 0.16 ( 0.84 ) 25

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3. 

For a hypothesis test of H0: p = 0.35 against the alternative Ha: p > 0.35, the z test statistic is found to be 2.45. What can be said about this finding? (2 points)

aThe finding is significant at α = 0.05 but not at α = 0.01.
bThe finding is significant at α = 0.01 but not at α = 0.05.
cThe finding is significant at both α = 0.05 and α = 0.01.
dThe finding is not significant at α = 0.05 and α = 0.01.
eThe finding is inconclusive because we don't know the value of p̂.

4. 

What conditions must be met to use z procedures in a significance test about a population proportion? (2 points)

  1. The sample size is greater than 30.
  2. The population is greater than 10 times the sample size.
  3. The probability of success multiplied by the sample size is greater than or equal to 10, and the probability of failure multiplied by the sample size is greater than or equal to 10.
aI only
bII only
cIII only
dI and II only
eII and III only

5. 

Football team members suspect the coin used for the coin toss at the beginning of their games is unfair. They believe it turns up tails more often than it should if it were fair. The coach of the team decides to flip the coin 100 times and count the number of tails. His trial results in 55 tails. He decides to carry out a significance test. What is the p-value he obtains and the general conclusion that can be made at a 95% significance level? (2 points)

aThe p-value is 0.159. He should reject the null in favor of the alternative.
bThe p-value is 0.159. He should fail to reject the null.
cThe p-value is 0.841. He should reject the null in favor of the alternative.
dThe p-value is 0.841. He should fail to reject the null.
eThere is not enough information provided to calculate the p-value and make a conclusion.

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