A portion of a ANOVA summary table is shown below.

source sum of squares degrees of freedom

between 17 3

within (error) 42 30

total 59

the critical value for this problem should have dfN (degrees of freedom in the numerator) and dfD (degrees of freedom in the denominator) of

solutions

a)dfN=17,dfD=42 b)dfN=3, dfD=30

c)dfN=42,dfD=17 d)dfN=30,dfD=3

a researcher is comparing samples from 6 different popultations. assume that the conclusion from an ANOVA is that the null hypothesis is rejected, in other words that the 6 population means are not all equal. we should expect that

solutions:

a)at least 1 of the comparisons of mean Xi verus Xj would be significant

b)at least 3 of the comparisons of mean Xi verus Xj would be significant

c)all 15 of the comparisons of means Xi versus Xj would be significant

d)at least 6 of the comparisons of means Xi versus Xj would be significant

source sum of squares degrees of freedom

between 17 3

within (error) 42 30

total 59

the critical value for this problem should have dfN (degrees of freedom in the numerator) and dfD (degrees of freedom in the denominator) of

solutions

a)dfN=17,dfD=42 b)dfN=3, dfD=30

c)dfN=42,dfD=17 d)dfN=30,dfD=3

a researcher is comparing samples from 6 different popultations. assume that the conclusion from an ANOVA is that the null hypothesis is rejected, in other words that the 6 population means are not all equal. we should expect that

solutions:

a)at least 1 of the comparisons of mean Xi verus Xj would be significant

b)at least 3 of the comparisons of mean Xi verus Xj would be significant

c)all 15 of the comparisons of means Xi versus Xj would be significant

d)at least 6 of the comparisons of means Xi versus Xj would be significant

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