View the step-by-step solution to:

305, ex 5 a. $20 n=49 Xbar = 20 20 +/- 1.96(5)/sqrt(49) pop. dev = 5 95% CI on mean spending 20 1.4 95%CL Z = 1.96 LL 18.6 Error= 1.40 UL 21.

P. 305, ex 5 a. $20
n=49
Xbar = 20 20 +/- 1.96(5)/sqrt(49)
pop. Std. dev = 5
95% CI on mean spending 20 1.4
95%CL Z = 1.96
LL 18.6
Error= 1.40 UL 21.4



6. Refer to the previous exercise. Suppose that 64 smokers (instead of 49) were sampled.
Assume the sample mean remained the same.

n=64
xbar=20
pop. Std. dev =5
95% Cl on mean spending
95%CL Z = 1.96




a. What is the 95 percent confidence interval estimate of µ ?
b. Explain why this confidence interval is narrower than the one determined in the
previous exercise.



Dr. Patton is a professor of English. Recently she counted the number of misspelled

Sign up to view the entire interaction

Top Answer

Dear Student, Thank you for... View the full answer

Sign up to view the full answer

Why Join Course Hero?

Course Hero has all the homework and study help you need to succeed! We’ve got course-specific notes, study guides, and practice tests along with expert tutors.

-

Educational Resources
  • -

    Study Documents

    Find the best study resources around, tagged to your specific courses. Share your own to gain free Course Hero access.

    Browse Documents
  • -

    Question & Answers

    Get one-on-one homework help from our expert tutors—available online 24/7. Ask your own questions or browse existing Q&A threads. Satisfaction guaranteed!

    Ask a Question
Ask a homework question - tutors are online