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Help me answer the matlab activity . Laplace Operator laplace...
Help me answer the matlab activity
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Laplace Operator laplace Laplace transform. L = laplace(F) is the Laplace transform of the sym F with default independent variable t. The default return is a function of s. If F = F(s), then laplace returns a function of z: L = L(z). By definition, L(s) = int(F(t)*exp(-s*t),t,0,inf). L = laplace(F,z) makes L a function of z instead of the default s: laplace(F,z) <=> L(z) = int(F(t)*exp(-z*t),t,0,inf). Example: syms t f(t) Defining the variables and function to be used f(t) = exp(2*t) *sin(4*t) Expressing your function and identify it as a function with t as independent variable. F = laplace(f) Exercises: Find the laplace transform of the following functions: 1. fi(t) = 1 2. f2(t) = (3et + 6sin5t + 212)2 3. fa(t) = (2sin(21) + 3cos(5t))3 4. fi(t) = sin(3t) x52 5. fs(t ) = 15 2<xx 0
Image transcription text
1 Find the Laplace transform of the given functions 2 * Initialize for symbolic processing 3 syms 4 % Define the given functions 6f1(t) = 6 f2 (t) = 7 f3(t) = 8 f4(t) = Hint : Check for the code heaviside 9 f5 (t) = 10 % Find the laplace transform of the given functions 11 F1 ( s) = 12 F2 (S) = 13 F3(s) = 14 F4 (s) = 15 F5 ( S) = 16
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