Asked by jkhanster
Please answer in matlab code: . 1975 1355 41 1976 1282 44 1977...
Please answer in matlab code:
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22.15 The motion of a damped spring-mass system ( Fig. P22.15) is described by the following ordinary differential equation: d' x dx m + kx = 0 d12 dt where x = displacement from equilibrium position (m), t = time (s), m = 20-kg mass, and c = the damping coefficient (N . s/m). The damping coefficient c takes on three values of 5 (underdamped), 40 (critically damped), and 200 (overdamped). The spring constant k = 20 N/m. The initial velocity is zero, and the initial displacement x = 1 m. Solve this equation using a numerical method over the time period 0 < t < 15 s. Plot the displacement versus time for each of the three values of the damping coefficient on the same plot. FIGURE P22.15 - X k 500 m C
Answered by tutormulain54
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